中文名称: D-(+)-半乳糖
英文名称: D-(+)-Galactose
CAS No: 59-23-4
分子式: C6H12O6
分子量: 180.16
EINEC: 200-416-4
G10009 D-(+)-半乳糖 ≥99% (psaitong)
熔点:
168-170°C
外观与性状:
白色粉末
包装规格:
25g 100g 500g 1kg in poly bottle
溶解性:
溶于水和吡啶
产品描述:

基本信息

产品编号:

G10009

产品名称:

D-(+)-Galactose

CAS:

59-23-4

 

储存条件

粉末

室温

四年

 

 

分子式:

C6H12O6

溶于液体

-80℃

两年

分子量

180.16

-20℃

一个月

化学名: 

(3R,4S,5R,6R)-6-(hydroxymethyl)oxane-2,3,4,5-tetrol

Solubility (25°C):

 

体外:

 

DMSO

36mg/mL (199.82mM)

Ethanol

 

Water

100mg/mL (555.06mM)

体内(现配现用):

1.请依序添加每种溶剂:PBS

Solubility: 130mg/mL (721.58mM); Clear solution; Need ultrasonic

2.请依序添加每种溶剂:10% DMSO40% PEG3005% Tween-8045% saline

Solubility: ≥ 2.5mg/mL (13.88mM); Clear solution

此⽅案可获得 ≥ 2.5mg/mL (13.88mM,饱和度未知) 的澄清溶液。 以 1mL ⼯作液为例,取 100μL 25.0mg/mL 的澄清 DMSO 储备液加到 400μL PEG300 中,混合均匀;向上述体系中加⼊ 50μL Tween-80,混合均匀;然后继续加⼊ 450μL ⽣理盐⽔定容⾄ 1mL

3.请依序添加每种溶剂:10% DMSO90% (20% SBE-β-CD in saline)

Solubility: ≥ 2.5mg/mL (13.88mM); Clear solution

此⽅案可获得 ≥ 2.5mg/mL (13.88mM,饱和度未知) 的澄清溶液。 以 1mL ⼯作液为例,取 100μL 25.0mg/mL 的澄清 DMSO 储备液加到 900μL 20% 的 SBE-β-CD ⽣理盐⽔⽔溶液中,混合均匀。

4.请依序添加每种溶剂:10% DMSO90% corn oil

Solubility: ≥ 2.5mg/mL (13.88mM); Clear solution

此⽅案可获得 ≥ 2.5mg/mL (13.88mM,饱和度未知) 的澄清溶液,此⽅案不适⽤于实验周期在半个⽉以上的实验。 以 1mL ⼯作液为例,取 100μL 25.0mg/mL 的澄清 DMSO 储备液加到 900μL ⽟⽶油中,混合均匀。

1mg/ml表示微溶或不溶。

普西唐提供的所有化合物浓度为内部测试所得,实际溶液度可能与公布值有所偏差,属于正常的批间细微差异现象。

请根据产品在不同溶剂中的溶解度选择合适的溶剂配制储备液;⼀旦配成溶液,请分装保存,避免反复冻融造成的产品失效。

 

制备储备液

 

浓度

 

溶液体积

质量

 

1mg

 

5mg

 

10mg

1mM

5.5506mL

27.7531mL

55.5062mL

5mM

1.1101mL

5.5506mL

11.1012mL

10mM

0.5551mL

2.7753mL

5.5506mL

50mM

0.1110mL

0.5551mL

1.1101mL

 

生物活性

产品描述

作为半乳糖基转移酶标记缓冲液的成分,在MRS肉汤中补充乳酸杆菌的生长,诱导解偶联蛋白(UCP)在酵母转化的表达。

靶点

Human Endogenous Metabolite

体外研究

Galactose is important for the survival and virulence of bacteria. In Escherichia coli galactose is utilized by the Leloir pathway. Two anomers of d-galactose are used for different purposes, α-d-galactose as a carbon source and β-d-galactose for induction of UDP-galactose synthesis for biosynthetic glycosylation

体内研究

Chronic D-galactose exposure induces neurodegeneration by enhancing caspase-mediated apoptosis and inhibiting neurogenesis and neuron migration in mice, as well as increasing oxidative damage. In addition, D-galactose-induced toxicity in mice is a useful model for studying the mechanisms of neurodegeneration and neuroprotective drugs and agents. D-galactose given by oral route causes cognitive impairments in rats which are accompanied by oxidative damage. Cognitive impairments is observed in the open-field test in the 4th and 6th weeks after d-gal administration, as well as an impairment in spatial memory in the radial maze test after the 6th week of d-gal administration

 

推荐实验方法(仅供参考)

Animal Administration

Rats: D-galactose is dissolved in water for administration at the dose of 100mg/kg of body weight, and given by oral gavage, once a day, over a period of 1, 2, 4, 6 or 8 weeks. Animals are randomized into two groups: control animals (receiving water by oral gavage) or d-gal animals (receiving D-galactose by oral gavage). The behavioral tests and biochemical analysis are undertaken on the1st, 2nd, 4th, 6th and 8th weeks after the last administration of d-gal

Mice: Male adult C57BL/6 mice are randomly divided into three groups (control, D-galactose, and D-galactose plus α-LA). Dgalactose (100mg/kg) is injected subcutaneously (s.c.) daily into mice for 7 weeks. α-LA (100mg/kg body weight) is injected peritoneally (i.p.) daily concomitantly for 7 weeks. All control animals are given saline

保存条件:
室温 干燥
UN码:
HazardClass:
危害声明:
安全说明:
搜索质检报告(COA)
参考文献 & 客户发表文献

本计算器可帮助您计算出特定溶液中溶质的质量、溶液浓度和体积之间的关系,公式为:
质量 (g) = 浓度 (mol/L) x 体积 (L) x 分子量 (g/mol)

摩尔浓度计算公式

  • =
    *
    *
    *选择对应的单位 *空出希望得到的变量,填写另外两个变量

用本工具协助配置特定浓度的溶液,使用的计算公式为:
开始浓度 x 开始体积 = 最终浓度 x 最终体积

稀释公式

稀释公式一般简略地表示为:C1V1 = C2V2 ( 输入 输出 )

  • * = *

连续稀释计算器方程

  • 连续稀释

  • 初始浓度:
  • 稀释倍数:
  • 计算结果

  • C1=C0/X C1: LOG(C1):
    C2=C1/X C2: LOG(C2):
    C3=C2/X C3: LOG(C3):
    C4=C3/X C4: LOG(C4):
    C5=C4/X C5: LOG(C5):
    C6=C5/X C6: LOG(C6):
    C7=C6/X C7: LOG(C7):
    C8=C7/X C8: LOG(C8):