中文名称: | NCH-51 | ||||
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英文名称: | NCH-51 | ||||
别名: | HDAC(组蛋白脱乙酰基酶) PTACH;S-(7-oxo-7-((4-phenylthiazol-2-yl)amino)heptyl) 2-methylpropanethioate | ||||
CAS No: | 848354-66-5 | 分子式: | C20H26N2O2S2 | 分子量: | 390.56 |
CAS No: | 848354-66-5 | ||||
分子式: | C20H26N2O2S2 | ||||
分子量: | 390.56 |
基本信息
产品编号:N10157 |
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产品名称:NCH-51 |
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CAS: |
848354-66-5 |
储存条件 |
粉末 |
-20℃ |
四年 |
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分子式: |
溶于液体 |
-80℃ |
六个月 |
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分子量 |
390.56 |
-20℃ |
一个月 |
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化学名: |
S-(7-Oxo-7-((4-phenylthiazol-2-yl)amino)heptyl) 2-methylpropanethioate |
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Solubility (25°C) |
体外 |
DMSO |
≥100mg/mL (256.04mM) |
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Ethanol |
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Water |
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体内 |
现配现用 |
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<1mg/ml表示微溶或不溶。 |
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普西唐提供的所有化合物浓度为内部测试所得,实际溶液度可能与公布值有所偏差,属于正常的批间细微差异现象。 |
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请根据产品在不同溶剂中的溶解度选择合适的溶剂配制储备液;⼀旦配成溶液,请分装保存,避免反复冻融造成的产品失效。 |
制备储备液
浓度
溶液体积 质量 |
1mg |
5mg |
10mg |
1mM |
2.5604mL |
12.8021mL |
25.6043mL |
5mM |
0.5121mL |
2.5604mL |
5.1209mL |
10mM |
0.2560mL |
1.2802mL |
2.5604mL |
生物活性
产品描述 |
一种HDAC抑制剂,抑制多种肿瘤细胞体外生长,EC50=1.1-9.1μM。 |
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靶点/IC50 |
HDAC1 48nM (IC50) |
HDAC4 32nM (IC50) |
HDAC6 41nM (IC50) |
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体外研究 |
PTACH (compound 51) treatment elevates the levels of acetylated histone H4 and p21WAF1/CIP1 in a dose-dependent manner.In cancer cell growth inhibition assay, PTACH (compound 51) shows strong activity. PTACH inhibits various cancer cells with EC50 values of 2.3μM, 9.1μM, 3.0μM, 2.6μM, 1.1μM, 4.5μM, 2.4μM, 5.0μM, and 4.5μM for MDA-MB-231, SNB-78, HCT116,NCI-H226, LOX-IMVI, SK-OV-3, RXF-631L, St-4, and DU-145 cells, respectively. PTACH (NCH-51) augments the HIV-1 production in latently infected OM10.1 cells and such reactivation is associated with a loss of HDAC1 occupancy and subsequent hyperacetylation of histones in nuc-1 at the HIV-1 promoter. Western Blot Analysis |
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Cell Line: |
Incubation Time: |
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Concentration: |
1μM, 5μM, 25μM |
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Incubation Time: |
8 hours |
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Incubation Time: |
Gave rise to elevated and dose-dependent levels of acetylated histone H4 and p21 WAF1/CIP1 . |
本计算器可帮助您计算出特定溶液中溶质的质量、溶液浓度和体积之间的关系,公式为:
质量 (g) = 浓度 (mol/L) x 体积 (L) x 分子量 (g/mol)
摩尔浓度计算公式
用本工具协助配置特定浓度的溶液,使用的计算公式为:
开始浓度 x 开始体积 = 最终浓度 x 最终体积
稀释公式
稀释公式一般简略地表示为:C1V1 = C2V2 ( 输入 输出 )